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# MODIFIED EULER'S METHOD

Posted By: Faith Hughes     Category: C Programming     Views: 25220

## Code for MODIFIED EULER'S METHOD in C Programming

```#include<stdio.h>
#include <math.h>
#include<conio.h>
#define F(x,y)  (x)*(x)+(y)
void main()
{
double y0,x0,y1,x1,y1_0,a,n,h,f,f1;
int j,count,flag;
clrscr();
printf("\nEnter the value of x0: ");
scanf("%lf",&x0);
printf("\nEnter the value of y0: ");
scanf("%lf",&y0);
printf("\nEnter the value of h: ");
scanf("%lf",&h);
printf("\nEnter the value of last point: ");
scanf("%lf",&n);
for(x1=x0+h,j=1; x1<=n+h; x1=x1+h,j++)
{
count=0;
flag=0;
f=F(x0,y0);
y1_0 = y0 + (h * f);
printf("\n\n * * y%d_0 = %.3lf * *",j,y1_0);
do
{
count++;
f=F(x0,y0);
f1=F(x1,y1_0);
y1 = y0 + h/2 * ( f + f1);
printf("\n\n * * x = %.3lf => y%d_%d = %.3lf * *",x1,j,count,y1);
if(fabs(y1-y1_0)<0.00001)
{
printf("\n\n\n\n * * * * y%d = %.3lf * * * *\n\n",j,y1);
flag=1;
}
else
y1_0 = y1;
}while(flag!=1);
y0 = y1;
}
getch();
}

/* OUT PUT---------Enter the value of x0: 0Enter the value of y0: 1Enter the value of h: 0.05Enter the value of last point: 0.1 * * y1_0 = 1.050 * * * * x = 0.050 => y1_1 = 1.051 * * * * x = 0.050 => y1_2 = 1.051 * * * * x = 0.050 => y1_3 = 1.051 * * * * * * y1 = 1.051 * * * * * * y2_0 = 1.104 * * * * x = 0.100 => y2_1 = 1.105 * * * * x = 0.100 => y2_2 = 1.106 * * * * x = 0.100 => y2_3 = 1.106 * * * * * * y2 = 1.106 * * * **/```
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 Faith Hughes author of MODIFIED EULER'S METHOD is from London, United Kingdom. View All Articles