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Program of FIXED POINT METHOD OF NON LINEAR EQUATION

Posted By: Lulu Fischer     Category: C Programming     Views: 4846

Write a program of FIXED POINT METHOD OF NON LINEAR EQUATION.

Code for Program of FIXED POINT METHOD OF NON LINEAR EQUATION in C Programming


#include<stdio.h>
#include<conio.h>
#include<math.h>
#define ESP 0.0001
#define F(x) 0.2*(x)*(x) - (x) + 0.8
#define G(x) 0.3*(x)*(y)*(y) - (y) + 0.7
#define X(x,y) 0.2*(x)*(x) + 0.8
#define Y(x,y) 0.3*(x)*(y)*(y) + 0.7
#define F1(x,y) 0.4*(x)
#define F2(x,y) 0
#define G1(x,y) 0.3*(y)*(y)
#define G2(x,y) 0.6*(x)*(y)


void main()
{
  float x1,y1,y2,x2,x,y;
  int i=1;
  clrscr();
  do
  {
  printf("\nEnter the value of x: ");
  scanf("%f",&x);
  printf("\nEnter the value of y: ");
  scanf("%f",&y);
  }while(fabs(F1(x,y)+F2(x,y)) > 1 && fabs(G1(x,y)+G2(x,y)) > 1);
  x1=X(x,y);
  y1=Y(x,y);
  printf("\n x = %f",x1);
  printf("\n y = %f",y1);
  printf("\n\n");
  do
  {
   x2=X(x1,y1);
   y2=Y(x1,y1);

  if(fabs(x1-x2)<ESP && fabs(y1-y2)<ESP)
  {
    printf("\n\nREAL ROOT1 = %.3f",x1);
    printf("\n\nREAL ROOT2 = %.3f",y1);
    i=0;
  }
  else
  {
   x1=x2;
   y1=y2;

  }
  if(i==1)
  {
   printf("\n x = %f",x1);
   printf("\n y = %f",y1);
   printf("\n\n");
  }
  }while(i!=0);
getch();
}

/*
____________________________

OUT PUT
____________________________

Enter the value of x:
Enter the value of y:
x = 0.850000
y = 0.737500


x = 0.944500
y = 0.838696


x = 0.978416
y = 0.899312


x = 0.991460
y = 0.937392


x = 0.996598
y = 0.961360


x = 0.998642
y = 0.976321


x = 0.999457
y = 0.985572


x = 0.999783
y = 0.991247


x = 0.999913
y = 0.994707


x = 0.999965
y = 0.996807


x = 0.999986
y = 0.998077


x = 0.999994
y = 0.998843


x = 0.999998
y = 0.999305


x = 0.999999
y = 0.999582


x = 1.000000
y = 0.999749


x = 1.000000
y = 0.999849



REAL ROOT1 = 1.000
REAL ROOT2 = 1.000
*/
  
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Lulu Fischer
Lulu Fischer author of Program of FIXED POINT METHOD OF NON LINEAR EQUATION is from Frankfurt, Germany.
 
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