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Program to copy the contents of one array to another without shared memory

Posted By: Rosie Hughes     Category: C Programming     Views: 2821

Program to copy the contents of one array to another without shared memory

Code for Program to copy the contents of one array to another without shared memory in C Programming

# include <stdio.h>
# include "forkjoin.h"int main()
{
    int arr1[10]={1,1,1,1,1,1,1,1,1,1};
    int arr2[10]={2,2,2,2,2,2,2,2,2,2};
    int id;
    int iCount;
    /* Copy Array-1 to Array-2 Using 2 Processes */
id=process_fork(2); if(id==0) { /* Parent Process */
for(iCount=0;iCount<10;iCount=iCount+2) { arr2[iCount]=arr1[iCount]; } } else { /* Child Process */
for(iCount=1;iCount<10;iCount=iCount+2) { arr2[iCount]=arr1[iCount]; } } process_join(2,id); /* Here Child Process is Completed
and We have not made Array 2 Shared So Changes made by
Child Process is not visible in Parent Process
*/
printf("\n Array 2 ... \n"); for(iCount=0;iCount<10;iCount++) { printf("arr2[%d] : %d\n",iCount,arr2[iCount]); } return 0; } /* Output

[divyen@localhost PP-TW1]$ ./Prog04

Array 2 ...
arr2[0] : 1
arr2[1] : 2
arr2[2] : 1
arr2[3] : 2
arr2[4] : 1
arr2[5] : 2
arr2[6] : 1
arr2[7] : 2
arr2[8] : 1
arr2[9] : 2

*/
  
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Rosie Hughes
Rosie Hughes author of Program to copy the contents of one array to another without shared memory is from London, United Kingdom.
 
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