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PROGRAM TO APPLY BLOCK SCHEDULING TECHNIQUE TO SOLVE FOLLOWING EXPRESSION X[I] = X[I+1] + Y[I]

Posted By: Bethany Hughes     Category: C Programming     Views: 1459

PROGRAM TO APPLY BLOCK SCHEDULING TECHNIQUE TO SOLVE FOLLOWING EXPRESSION X[I] = X[I+1] + Y[I].

Code for PROGRAM TO APPLY BLOCK SCHEDULING TECHNIQUE TO SOLVE FOLLOWING EXPRESSION X[I] = X[I+1] + Y[I] in C Programming

#include <stdio.h>
#include "forkjoin.h"
#include "shared.h"
#include "barrier.h"

main()
{
         float *x,*xsav,*y,*ysav;
         int *imin,*imax,iexcess,size;
         int *bar,nproc,i,pid,npts;
         int shmid1,shmid2,shmid3,shmid4,shmid5,shmid6,shmid7;
        
         printf("Enter the size of the Array : ");
         scanf("%d",&size);
         printf("Enter the no of process : ");
         scanf("%d",&nproc);
         x = (float *)create_memory(4*size,&shmid1);
         y = (float *)create_memory(4*size,&shmid6);
         xsav = (float *)create_memory(4*size,&shmid2);
         ysav = (float *)create_memory(4*size,&shmid7);
         imin = (int *)create_memory(2*size,&shmid3);
         imax = (int *)create_memory(2*size,&shmid4);
         bar = (int *)create_memory(2*4,&shmid5);
         
         printf("Enter the Elements of the Array x :\n");
         for(i=1;i<=size;i++)
         {
              printf("%d Element : ",i);
              scanf("%f",&x[i]);
         }
         printf("\nEnter the Elements of the Array y :\n");
         for(i=1;i<=size;i++)
         {
              printf("%d Element : ",i);
              scanf("%f",&y[i]);
         }
         barrier_init(bar,nproc);
         pid = create_process(&nproc);
         npts = size/nproc;
         iexcess = 0;
         iexcess = size-(nproc*npts);
         if(iexcess == 0)
         {
                imax[pid] = imax[pid]=0;
                imin[pid] = (pid*npts)+1;
                imax[pid] = (pid * npts) + npts;
         }
         else
         {
                if(pid<iexcess)
                {
                      imax[pid] = imax[pid]=0;
                      imin[pid] = pid * (npts + 1) + 1;
                      imax[pid] = imin[pid] + npts;
                }
                else
                {
                      imax[pid] = imax[pid]=0;
                      imin[pid] = (pid * npts) + 1 + iexcess;
                      imax[pid] = imin[pid] + npts - 1;
                }
         }
         xsav[pid] = x[imax[pid] + 1];
         ysav[pid] = y[imax[pid] + 1];
         barrier(bar);
         for(i=imin[pid];i<imax[pid];i++)
         {
                x[i] = x[i+1]+y[i];
         }
         if(imax[pid]!=size)
               x[imax[pid]] = xsav[pid]+ysav[pid];
         join_process(&nproc,&pid);
         printf("\nThe New Array is : \n");
         for(i=1;i<=size;i++)
               printf("\n%d Element : %f",i,x[i]);
         printf("\n");
         cleanup_memory(&shmid1);
         cleanup_memory(&shmid2);
         cleanup_memory(&shmid3);
         cleanup_memory(&shmid4);
         cleanup_memory(&shmid5);
         cleanup_memory(&shmid6);
         cleanup_memory(&shmid7);
}                 
          
/**************************************************************************

          :: OUTPUT ::

    Enter the size of the Array : 5
    Enter the no of process : 4

    Enter the Elements of the Array x :

    1 Element : 1
    2 Element : 2
    3 Element : 3
    4 Element : 4
    5 Element : 5

    Enter the Elements of the Array y :

    1 Element : 6
    2 Element : 7
    3 Element : 8
    4 Element : 9
    5 Element : 10
    
    The New Array is : 
    
    1 Element : 8.000000
    2 Element : 11.000000
    3 Element : 13.000000
    4 Element : 15.000000
    5 Element : 5.000000
  
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Bethany Hughes
Bethany Hughes author of PROGRAM TO APPLY BLOCK SCHEDULING TECHNIQUE TO SOLVE FOLLOWING EXPRESSION X[I] = X[I+1] + Y[I] is from London, United Kingdom.
 
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