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Program to convert a Postfix Expression into an Infix Expression

Posted By: Easy Tutor     Category: C++ Programming     Views: 85470

A C++ Program to convert a Postfix Expression into an Infix Expression.

Code for Program to convert a Postfix Expression into an Infix Expression in C++ Programming

 # include <iostream.h>
 # include   <string.h>
 # include   <stdlib.h>
 # include    <conio.h>

 int top=-1;

 char Stack[25][100]={NULL};

 void push(constchar *);
 constchar* pop( );

 void postfix_to_infix(constchar *);

 int main( )
    {
       clrscr( );

       char Postfix_expression[100]={NULL};

       cout<<"\n\n\t Enter the Postfix Expression : ";
       cin.getline(Postfix_expression,80);

       postfix_to_infix(Postfix_expression);

       getch( );
       return 0;
    }


 /*************************************************************************///-----------------------------  push(const char)  ----------------------///*************************************************************************/void push(constchar *Symbol)
    {
       if(top==24)
      cout<<"Error : Stack is full."<<endl;

       else
      {
         top++;
         strcpy(Stack[top],Symbol);
      }
    }

 /*************************************************************************///--------------------------------  pop( )  -----------------------------///*************************************************************************/constchar* pop( )
    {
       char Symbol[100]={NULL};

       if(top==-1)
      cout<<"Error : Stack is empty."<<endl;

       else
      {
         strcpy(Symbol,Stack[top]);
         strset(Stack[top],NULL);
         top--;
      }

       return Symbol;
    }

 /*************************************************************************///---------------------  postfix_to_infix(const char *)  ----------------///*************************************************************************/void postfix_to_infix(constchar *Postfix)
    {
       char Infix_expression[100]={NULL};
       char Postfix_expression[100]={NULL};

       strcpy(Postfix_expression,Postfix);
       strcat(Postfix_expression,"=");

       int count=0;

       char Symbol_scanned[5]={NULL};

       do
      {
         Symbol_scanned[0]=Postfix_expression[count];

         if(Symbol_scanned[0]=='/' || Symbol_scanned[0]=='*' ||
        Symbol_scanned[0]=='-' || Symbol_scanned[0]=='+' ||
                       Symbol_scanned[0]=='^' )
        {
           char Value_1[100]={NULL};
           char Value_2[100]={NULL};
           char Result[100]={NULL};

           strcpy(Value_1,pop( ));
           strcpy(Value_2,pop( ));

           if(Infix_expression[(count+1)]!='=')
              strcpy(Result,"(");

           strcat(Result,Value_2);
           strcat(Result,Symbol_scanned);
           strcat(Result,Value_1);

           if(Infix_expression[(count+1)]!='=')
              strcat(Result,")");

           push(Result);
        }

         else
        push(Symbol_scanned);

         count++;
      }
       while(Postfix_expression[count]!='=');

       strset(Infix_expression,NULL);
       strcpy(Infix_expression,pop( ));

       cout<<"\n\n\t Infix Expression is : "<<Infix_expression;
    }
  
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Easy Tutor
Easy Tutor author of Program to convert a Postfix Expression into an Infix Expression is from United States. Easy Tutor says

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