Logo 
Search:

C Programming Articles

Submit Article
Home » Articles » C Programming » Data File StructureRSS Feeds

Program which maintains a B-tree of order 5

Posted By: Mohammed Evans     Category: C Programming     Views: 8995

Program which maintains a B-tree of order 5.

Code for Program which maintains a B-tree of order 5 in C Programming

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <alloc.h>

#define MAX 4
#define MIN 2

struct btnode
{
    int count ;
    intvalue[MAX + 1] ;
    struct btnode *child[MAX + 1] ;
} ;

struct btnode * insert ( int, struct btnode * ) ;
int setval ( int, struct btnode *, int *, struct btnode ** ) ;
struct btnode * search ( int, struct btnode *, int * ) ;
int searchnode ( int, struct btnode *, int * ) ;
void fillnode ( int, struct btnode *, struct btnode *, int ) ;
void split ( int, struct btnode *, struct btnode *,
                int, int *, struct btnode ** ) ;
struct btnode * delete ( int, struct btnode * ) ;
int delhelp ( int, struct btnode * ) ;
void clear ( struct btnode *, int ) ;
void copysucc ( struct btnode *, int ) ;
void restore ( struct btnode *, int ) ;
void rightshift ( struct btnode *, int ) ;
void leftshift ( struct btnode *, int ) ;
void merge ( struct btnode *, int ) ;
void display ( struct btnode * ) ;

void main( )
{
    struct node *root ;
    root = NULL ;

    clrscr( ) ;

    root = insert ( 27, root ) ;
    root = insert ( 42, root ) ;
    root = insert ( 22, root ) ;
    root = insert ( 47, root ) ;
    root = insert ( 32, root ) ;
    root = insert ( 2, root ) ;
    root = insert ( 51, root ) ;
    root = insert ( 40, root ) ;
    root = insert ( 13, root ) ;

    printf ( "B-tree of order 5:\n" ) ;
    display ( root ) ;

    root = delete ( 22, root ) ;
    root = delete ( 11, root ) ;

    printf ( "\n\nAfter deletion of values:\n" ) ;
    display ( root ) ;

    getch( ) ;
}

/* inserts a value in the B-tree*/
struct btnode * insert ( int val, struct btnode *root ) { int i ; struct btnode *c, *n ; int flag ; flag = setval ( val, root, &i, &c ) ; if ( flag ) { n = ( struct btnode * ) malloc ( sizeof ( struct btnode ) ) ; n -> count = 1 ; n -> value [1] = i ; n -> child [0] = root ; n -> child [1] = c ; return n ; } return root ; } /* sets the value in the node */
int setval ( int val, struct btnode *n, int *p, struct btnode **c ) { int k ; if ( n == NULL ) { *p = val ; *c = NULL ; return 1 ; } else { if ( searchnode ( val, n, &k ) ) printf ( "\nKey value already exists.\n" ) ; if ( setval ( val, n -> child [k], p, c ) ) { if ( n -> count < MAX ) { fillnode ( *p, *c, n, k ) ; return 0 ; } else { split ( *p, *c, n, k, p, c ) ; return 1 ; } } return 0 ; } } /* searches value in the node */
struct btnode * search ( int val, struct btnode *root, int *pos ) { if ( root == NULL ) return NULL ; else { if ( searchnode ( val, root, pos ) ) return root ; elsereturn search ( val, root -> child [*pos], pos ) ; } } /* searches for the node */
int searchnode ( int val, struct btnode *n, int *pos ) { if ( val < n -> value [1] ) { *pos = 0 ; return 0 ; } else { *pos = n -> count ; while ( ( val < n -> value [*pos] ) && *pos > 1 ) ( *pos )-- ; if ( val == n -> value [*pos] ) return 1 ; elsereturn 0 ; } } /* adjusts the value of the node */
void fillnode ( int val, struct btnode *c, struct btnode *n, int k ) { int i ; for ( i = n -> count ; i > k ; i-- ) { n -> value [i + 1] = n -> value [i] ; n -> child [i + 1] = n -> child [i] ; } n -> value [k + 1] = val ; n -> child [k + 1] = c ; n -> count++ ; } /* splits the node */
void split ( int val, struct btnode *c, struct btnode *n, int k, int *y, struct btnode **newnode ) { int i, mid ; if ( k <= MIN ) mid = MIN ; else mid = MIN + 1 ; *newnode = ( struct btnode * ) malloc ( sizeof ( struct btnode ) ) ; for ( i = mid + 1 ; i <= MAX ; i++ ) { ( *newnode ) -> value [i - mid] = n -> value [i] ; ( *newnode ) -> child [i - mid] = n -> child [i] ; } ( *newnode ) -> count = MAX - mid ; n -> count = mid ; if ( k <= MIN ) fillnode ( val, c, n, k ) ; else fillnode ( val, c, *newnode, k - mid ) ; *y = n -> value [n -> count] ; ( *newnode ) -> child [0] = n -> child [n -> count] ; n -> count-- ; } /* deletes value from the node */
struct btnode * delete ( int val, struct btnode *root ) { struct btnode * temp ; if ( ! delhelp ( val, root ) ) printf ( "\nValue %d not found.", val ) ; else { if ( root -> count == 0 ) { temp = root ; root = root -> child [0] ; free ( temp ) ; } } return root ; } /* helper function for delete( ) */
int delhelp ( int val, struct btnode *root ) { int i ; int flag ; if ( root == NULL ) return 0 ; else { flag = searchnode ( val, root, &i ) ; if ( flag ) { if ( root -> child [i - 1] ) { copysucc ( root, i ) ; flag = delhelp ( root -> value [i], root -> child [i] ) ; if ( !flag ) printf ( "\nValue %d not found.", val ) ; } else clear ( root, i ) ; } else flag = delhelp ( val, root -> child [i] ) ; if ( root -> child [i] != NULL ) { if ( root -> child [i] -> count < MIN ) restore ( root, i ) ; } return flag ; } } /* removes the value from the node and adjusts the values */
void clear ( struct btnode *node, int k ) { int i ; for ( i = k + 1 ; i <= node -> count ; i++ ) { node -> value [i - 1] = node -> value [i] ; node -> child [i - 1] = node -> child [i] ; } node -> count-- ; } /* copies the successor of the value that is to be deleted */
void copysucc ( struct btnode *node, int i ) { struct btnode *temp ; temp = node -> child [i] ; while ( temp -> child[0] ) temp = temp -> child [0] ; node -> value [i] = temp -> value [1] ; } /* adjusts the node */
void restore ( struct btnode *node, int i ) { if ( i == 0 ) { if ( node -> child [1] -> count > MIN ) leftshift ( node, 1 ) ; else merge ( node, 1 ) ; } else { if ( i == node -> count ) { if ( node -> child [i - 1] -> count > MIN ) rightshift ( node, i ) ; else merge ( node, i ) ; } else { if ( node -> child [i - 1] -> count > MIN ) rightshift ( node, i ) ; else { if ( node -> child [i + 1] -> count > MIN ) leftshift ( node, i + 1 ) ; else merge ( node, i ) ; } } } } /* adjusts the values and children while shifting the value from parent to right
child */
void rightshift ( struct btnode *node, int k ) { int i ; struct btnode *temp ; temp = node -> child [k] ; for ( i = temp -> count ; i > 0 ; i-- ) { temp -> value [i + 1] = temp -> value [i] ; temp -> child [i + 1] = temp -> child [i] ; } temp -> child [1] = temp -> child [0] ; temp -> count++ ; temp -> value [1] = node -> value [k] ; temp = node -> child [k - 1] ; node -> value [k] = temp -> value [temp -> count] ; node -> child [k] -> child [0] = temp -> child [temp -> count] ; temp -> count-- ; } /* adjusts the values and children while shifting the value from parent to left
child */
void leftshift ( struct btnode *node, int k ) { int i ; struct btnode *temp ; temp = node -> child [k - 1] ; temp -> count++ ; temp -> value [temp -> count] = node -> value [k] ; temp -> child [temp -> count] = node -> child [k] -> child [0] ; temp = node -> child [k] ; node -> value [k] = temp -> value [1] ; temp -> child [0] = temp -> child [1] ; temp -> count-- ; for ( i = 1 ; i <= temp -> count ; i++ ) { temp -> value [i] = temp -> value [i + 1] ; temp -> child [i] = temp -> child [i + 1] ; } } /* merges two nodes */
void merge ( struct btnode *node, int k ) { int i ; struct btnode *temp1, *temp2 ; temp1 = node -> child [k] ; temp2 = node -> child [k - 1] ; temp2 -> count++ ; temp2 -> value [temp2 -> count] = node -> value [k] ; temp2 -> child [temp2 -> count] = node -> child [0] ; for ( i = 1 ; i <= temp1 -> count ; i++ ) { temp2 -> count++ ; temp2 -> value [temp2 -> count] = temp1 -> value [i] ; temp2 -> child [temp2 -> count] = temp1 -> child [i] ; } for ( i = k ; i < node -> count ; i++ ) { node -> value [i] = node -> value [i + 1] ; node -> child [i] = node -> child [i + 1] ; } node -> count-- ; free ( temp1 ) ; } /* displays the B-tree */
void display ( struct btnode *root ) { int i ; if ( root != NULL ) { for ( i = 0 ; i < root -> count ; i++ ) { display ( root -> child [i] ) ; printf ( "%d\t", root -> value [i + 1] ) ; } display ( root -> child [i] ) ; } }
  
Share: 


Didn't find what you were looking for? Find more on Program which maintains a B-tree of order 5 Or get search suggestion and latest updates.

Mohammed Evans
Mohammed Evans author of Program which maintains a B-tree of order 5 is from London, United Kingdom.
 
View All Articles

 
Please enter your Comment

  • Comment should be atleast 30 Characters.
  • Please put code inside [Code] your code [/Code].

 
No Comment Found, Be the First to post comment!