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Nested Structure Database Program

Posted By: Easy Tutor     Category: C++ Programming     Views: 6853

Write a program which performs nested structure database operation in C++.

Code for Nested Structure Database Program in C++ Programming

/*www.DailyFreeCode.comDownload Projects, Sourcecodes, Tips and Tricks, Interview FAQs, Hotlinks and more....Logon to www.DailyFreeCode.com*///samp Program of colledge dt.17/7/00//To Enter Few Records and to sort according to the choice of//the data member.   (USING NESTED STRUCTURE)

#include <iostream.h>
#include <iomanip.h>
#include <conio.h>

//GLOBAL DECLARATION OF STRUCTUREstruct date
{
int year,month,day;
};

struct person
{
int recno;
char name[20];
date dob;          //using date structure as datatypeint salary;
};

void line(void);    //Global Declaration of function as it is called in another function other than main.void main()
{
void starting(void);
void sorting(struct person[],int);
void display(struct person[]);
void end(void);
person rec[5];            //Declaration of person datatype

starting();

textcolor(111);
textbackground(196);
clrscr();
 cout<<"\n\n"<<setw(48)<<"RECORD INFORMATION";
//for inserting records
cout<<"\n\n\n\n\tEnter 5 Records\n\n\n\n";
for(int i=0,c=1;i<5;i++)
{

    cout<<"Information for Record No. "<<c<<endl;
       c++;
    line();
    cout<<"\n\nEnter Record Number:-";
   cin>>rec[i].recno;
    cout<<"Enter Name :-";
   cin>>rec[i].name;
   cout<<"\nFOR Birth_Date\n";
   cout<<"--------------\n";
   cout<<"Enter Year:-";
   cin>>rec[i].dob.year;
   cout<<"Enter Month:-";
   cin>>rec[i].dob.month;
   cout<<"Enter Day:-";
   cin>>rec[i].dob.day;
   cout<<"\nEnter salary:-";
   cin>>rec[i].salary;
   line();
   cout<<endl<<endl;
}

clrscr();
display(rec);
clrscr();
cout<<endl<<endl;
int choice;
do
{
cout<<endl<<endl;
cout<<"\n\nWhat Operation Would you Like to Perform\n";
cout<<"1)    sort by Record Number\n";
cout<<"2)    sort by Name\n";
cout<<"3)    sort by Date\n";
cout<<"4)    sort by Salary\n";
cout<<"5)    DISPLAYING\n";
cout<<"6)    QUIT\n";
cout<<"Enter Your Choice:-";
cin>>choice;
    switch(choice)
    {
    case     1:
    case     2:
    case     3:
   case    4:sorting(rec,choice);
                 break;
    case     5:display(rec);
               break;
   case    6:gotoout;
    default:cout<<"Entered Choice is Invalid, Try Again";
    }
   getch();
   clrscr();
}while(1);
out:
}


//sorting  functionvoid sorting(struct person rec[],int choice)
{
 struct person tempq;

         //record Number wise Sortingif(choice==1)
      {
          for(int i=0;i<5;i++)
         {
             for(int j=i+1;j<5;j++)
            {
                if(rec[i].recno > rec[j].recno)
               {
                tempq        =    rec[i];
               rec[i]    =    rec[j];
               rec[j]    =    tempq;
               }
            }
         }
      }


   //namewise sortingif(choice==2)
   {
       for(int i=0;i<5;i++)
      {
          for(int j=i+1;j<5;j++)
         {
             if(strcmp(rec[i].name,rec[j].name)>0)
                {
               tempq                  =  rec[i];
               rec[i]                =  rec[j];
               rec[j]              =  tempq;
               }
         }
      }
    }

    //datewiseif(choice==3)
   {
    for(int i=0;i<5;i++)
   {
       for(int j=i+1;j<5;j++)
      {
            if(rec[i].dob.year > rec[j].dob.year)
             {
                tempq                  =  rec[i];
               rec[i]                =  rec[j];
               rec[j]              =  tempq;

               if(rec[i].dob.month > rec[j].dob.month)
                   {
                  tempq                =   rec[i];
                  rec[i]            =     rec[j];
                  rec[j]            =   tempq;

                      if(rec[i].dob.day > rec[j].dob.day)
                      {
                      tempq                    =    rec[i];
                      rec[i]                =  rec[j];
                      rec[j]                =  tempq;
                      }

                  }
               }
         }
      }
     }


     //for salary wiseif(choice==4)
     {
        for(int i=0;i<5;i++)
       {
           for(int j=i+1;j<5;j++)
          {
          if(rec[i].salary > rec[j].salary)
         {
                  tempq            =   rec[i];
                 rec[i]           =     rec[j];
                rec[j]        =   tempq;
         }
      }
   }
  }

}



//display functionvoid display(struct person rec[])
{
textcolor(106);
textbackground(104);
clrscr();
cout<<endl<<endl<<endl;
line();
cout<<setw(10)<<"Record No."<<setw(25)<<"NAME OF PERON"<<setw(20)<<"DATE OF BIRTH"<<setw(23)<<"SALARY AT PRESENT"<<endl;
line();
for(int i=0;i<5;i++)
{
cout<<endl;
cout<<setw(6)<<rec[i].recno;
cout<<setw(27)<<rec[i].name;
cout<<setw(15)<<rec[i].dob.day<<"\\"<<rec[i].dob.month<<"\\"<<rec[i].dob.year;
cout<<setw(15)<<rec[i].salary;
cout<<endl;
}
getch();
}


//Line function
void line(void)
{
    for(int i=0;i<40;i++)
    {
        cout<<"--";
    }
   cout<<endl;
}


//Starting function
void starting(void)
{
 //START OF programer details\ textcolor(105);
 textbackground(104);
clrscr();
cout<<endl;
cout<<"|";
for(int i=0;i<39;i++)
{
        cout<<"--";
}
cout<<"|";

cout<<"";
for(int i=0;i<34;i++)
    cout<<"=";

cout<<"VIVEK PATEL";

for(int i=0;i<33;i++)
    cout<<"=";

cout<<endl;

cout<<"|";
for(int i=0;i<39;i++)
{
        cout<<"--";
}
cout<<"|";
cout<<endl<<endl<<endl;
line();
cout<<setw(49)<<"WELLCOME VIEWERS\n";
line();
cout<<setw(55)<<"SAMPLE DATABASE APPLICATION\n\n";
line();
line();
cout<<setw(79)<<"Created By VIVEK PATEL\n\n";
line();
line();
cout<<setw(55)<<"EMAIL US AT VIVEK_P9@HOTMAIL.COM";
getch();

//END OF PROGRAMMER DETAILS\\
}
  
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Easy Tutor author of Nested Structure Database Program is from United States. Easy Tutor says

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