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# Program to illustrate friend function

Posted By: Easy Tutor     Category: C++ Programming     Views: 22296

## Code for Program to illustrate friend function in C++ Programming

```/*www.DailyFreeCode.comDownload Projects, Sourcecodes, Tips and Tricks, Interview FAQs, Hotlinks and more....Logon to www.DailyFreeCode.com*///create two classes DM and DB which stores the value of distances. DM stores distances in metres//and centimetres and DB in feet and inches. Write a program that can read values for the class objects//and add one object DM with another object of DB.//use friend function.

#include <iostream.h>
#include <conio.h>

class db;

class dm
{
float mt;
int cm;
public:
void getdata(void);
void display(void);
};

class db
{
int feet;
float inches;
public:
void getdata(void);
void display(void);
};

void dm :: getdata(void)
{
clrscr();
cout<<"\t\tDM GETDATA FUNCTION\n\n";
cout<<"\n\nEnter Values for metres :-";
cin>>mt;
cout<<"Enter Values for centimetres:-";
cin>>cm;
}
void dm :: display(void)
{
cout<<"\n\nThe value of distance in metres is "<<mt;
cout<<"\nThe value of distance in Centimetres is "<<cm;
}

void db :: getdata(void)
{
clrscr();
cout<<"\t\tDB GETDATA FUNCTION\n\n";
cout<<"\n\nEnter Values for feet :-";
cin>>feet;
cout<<"Enter Values for inches :-";
cin>>inches;
}
void db :: display(void)
{
cout<<"\n\nThe value of distance in feet is "<<feet;
cout<<"\nThe value of distance in inches is "<<inches;
}

{
dm temp;
temp.cm=a.cm+(b.feet*30)+((b.inches*30)/12.0);
temp.mt=a.mt+(temp.cm % 100);
temp.cm=temp.cm-((temp.cm % 100)*100);
return(temp);
}

void main()
{
dm a;
a.getdata();
db b;
b.getdata();

clrscr();
cout<<"\n\t\tAFTER CONVERSION AND THEIR ADDITION IS PERFORMED\n";

//extra variable of type dm to display result of adding two different types of distance
dm extra;
extra.display();

getch();
}```
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