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# FUNCTION TABULATED AT EQUAL INTERVAL USING BACKWARD DIFFERENCE BETWEEN TWO VALUE

Posted By: Audris Schmidt     Category: C Programming     Views: 4293

## Code for FUNCTION TABULATED AT EQUAL INTERVAL USING BACKWARD DIFFERENCE BETWEEN TWO VALUE in C Programming

```#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float x[10],y[10][10],sum,p,u,temp,temp1;
int i,n,j,k=0,f,m,l=0;
float fact(int);
clrscr();
printf("\nhow many record you will be enter: ");
scanf("%d",&n);
for(i=0; i<n; i++)
{
printf("\n\nenter the value of x%d: ",i);
scanf("%f",&x[i]);
printf("\n\nenter the value of f(x%d): ",i);
scanf("%f",&y[k][i]);
}
printf("\n\nEnter X for finding f(x): ");
scanf("%f",&p);

for(i=1;i<n;i++)
{
for(j=i;j<n;j++)
{
y[i][j]=y[i-1][j]-y[i-1][j-1];
}
}
printf("\n_____________________________________________________\n");
printf("\n  x(i)\t   y(i)\t    y1(i)    y2(i)    y3(i)    y4(i)");
printf("\n_____________________________________________________\n");
for(i=0;i<n;i++)
{
printf("\n %.3f",x[i]);
for(j=0;j<=i;j++)
{
printf("   ");
printf(" %.3f",y[j][i]);
}
printf("\n");
}

i=0;
do
{
if(x[i]<p && p<x[i+1])
k=1;
else
i++;
}while(k != 1);
f=i;
n=f+1;
sum=0;
for(i=1;i<n;i++)
{
temp=1,temp1=0;
for(j=1;j<i;j++)
{
if(l==0)
{
temp = temp * (u+(u + j));
l=1;
}
else
{
temp1 = temp1 + u*(u+j);
temp = temp * (u+j);
}
}
m=fact(i);
temp=temp+temp1;
sum = sum + temp*(y[i][f]/m);
}
sum = sum/(x[1]-x[0]);
printf("\n\n f(%.2f) = %f ",p,sum);
getch();
}

float fact(int a)
{
float fac = 1;

if (a == 0)
return (1);
else
fac = a * fact(a-1);

return(fac);
}

/*______________________________________         OUT PUT______________________________________how many record you will be enter: 5enter the value of x0: 2.5enter the value of f(x0): 9.75enter the value of x1: 3.0enter the value of f(x1): 12.45enter the value of x2: 3.5enter the value of f(x2): 15.70enter the value of x3: 4.0enter the value of f(x3): 19.52enter the value of x4: 4.5enter the value of f(x4): 23.75Enter X for finding f(x): 4.25_____________________________________________________  x(i)     y(i)     y1(i)    y2(i)    y3(i)    y4(i)_____________________________________________________ 2.500    9.750 3.000    12.450    2.700 3.500    15.700    3.250    0.550 4.000    19.520    3.820    0.570    0.020 4.500    23.750    4.230    0.410    -0.160    -0.180 f(4.25) = 8.223335*/```
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 Audris Schmidt author of FUNCTION TABULATED AT EQUAL INTERVAL USING BACKWARD DIFFERENCE BETWEEN TWO VALUE is from Frankfurt, Germany. View All Articles

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