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PROGRAM TO FIND THE POSSIBLE VALUE OF ? SIGN USING TIME SERIES

Posted By: Harry Evans     Category: C Programming     Views: 2006

PROGRAM TO FIND THE POSSIBLE VALUE OF ? SIGN USING TIME SERIES

YEAR PRICE

1995 10
1996 12
1997 11
1998 13
1999 14
2000 17
2001 18
2002 15
2003 17
2004 ?

Code for PROGRAM TO FIND THE POSSIBLE VALUE OF ? SIGN USING TIME SERIES in C Programming

#include <stdio.h>
#include "forkjoin.h"
#include "shared.h"
#include "barrier.h"int main()
{    
        int pid,nproc,*bar,shmid1,shmid2,shmid3,shmid4,shmid5,shmid6;
        int shmid7,size,i,shmid8,shmid9,shmid10,shmid11,shmid12,shmid13;
        float *sumy,*sumxy,*sumx2,*a,*b,*yc,ye;
        float *x,*xy,dis,*mean,sum,*year,*x2,*y;

        printf("Enter the size : ");
        scanf("%d",&size);
        x = (float *) create_memory(4*size,&shmid1);
        y = (float *) create_memory(4*size,&shmid2);
        xy = (float *) create_memory(4*size,&shmid3);
        mean  = (float *)create_memory(4,&shmid4);
        bar = (int *) create_memory(2*4,&shmid5);
        year = (float *) create_memory(4*size,&shmid6);
        x2 = (float *) create_memory(4*size,&shmid7);
        sumy = (float *) create_memory(4,&shmid8);
        sumxy = (float *) create_memory(4,&shmid9);
        sumx2 = (float *) create_memory(4,&shmid10);
        a = (float *) create_memory(4,&shmid11);
        b = (float *) create_memory(4,&shmid12);
        yc = (float *) create_memory(4*size , &shmid13);
        *mean = 0;      
        *sumy=0;
        *sumx2=0;
        *sumxy=0;
       
        printf("Enter the year and corresponding production :\n");
        for(i=0;i<size;i++)
        {
              printf("%d    Year : ",i+1 );
              scanf("%f",&year[i]);
              printf("Production : ");
              scanf("%f",&y[i]);
        }
        dis = year[2] - year[1]; 
        printf("\nEnter the no of process : \n");
        scanf("%d",&nproc); 
        barrier_init(bar,nproc);
        *mean=0;
        pid = create_process(&nproc);
        sum =0 ;
        for(i=pid;i<size;i+=nproc)
              sum += year[i];
        barrier(bar);

        (*mean)+=sum/size;
        barrier(bar);
        for(i=pid;i<size;i+=nproc)
        {
               x[i] = x2[i] = xy[i] = 0;
               x[i] = (year[i] - (*mean))/dis;
               x2[i] = x[i]*x[i];
               xy[i] = x[i] * y[i];
               (*sumy) += y[i];
               (*sumxy) += xy[i];
               (*sumx2) += x2[i];  
               
        }
        barrier(bar);
        if(pid == 0)
        {
                *a = (*sumy)/size;
                *b = (*sumxy)/(*sumx2);
        }
        barrier(bar);
        for(i=pid;i<size;i+=nproc)
        {
                yc[i] = (*a) + ((*b)*(x[i]));
        }
        join_process(&nproc,&pid);
        printf("\nYear\ty\tx\tx2\txy\tyc   \n" );
        printf("\n-----------------------------------------------
                ---------------------\n");
        for(i=0;i<size;i++)
        {
               printf("%f\t %f\t %f \t %f\t %f \t %f \n",year[i],
                       y[i],x[i],x2[i],xy[i],yc[i]);
        }
        printf("\ny = %f\t xy = %f\t x2 = %f\t a = %f\t b = %f \t",
                  *sumy,*sumxy,*sumx2,*a,*b);
        printf("Enter the Year for finding the treand value : ");
        scanf("%f",&ye);
        x[size] =0;
        yc[size] =0;
        x[size] = (ye - (*mean))/dis;
        yc[size] = (*a) + ((*b)*(x[size]));
        printf("\nThe Trend Values for Year %f is %f ",ye,yc[size]);
        printf("\n");
        
        cleanup_memory(&shmid1);
        cleanup_memory(&shmid2);
        cleanup_memory(&shmid3);
        cleanup_memory(&shmid4);
        cleanup_memory(&shmid5);
        cleanup_memory(&shmid6);
        cleanup_memory(&shmid7);
        cleanup_memory(&shmid8);
        cleanup_memory(&shmid9);
        cleanup_memory(&shmid10);
        cleanup_memory(&shmid11);
        cleanup_memory(&shmid12);
        cleanup_memory(&shmid13);
        return 0;
}
              

/*        :: OUTPUT ::


Enter the size : 9

Enter the year and corresponding production :
1 Year : 1995
Production : 10

2 Year : 1996
Production : 12

3 Year : 1997
Production : 11

4 Year : 1998
Production : 13

5 Year : 1999
Production : 14

6 Year : 2000
Production : 17

7 Year : 2001
Production : 18

8 Year : 2002
Production : 15

9 Year : 2003
Production : 17

Enter the no of process :
3

Year y x x2 xy yc
-----------------------------------------------------------------
1995.000000 10.000000 -4.000122 16.000977 -40.001221 10.44536619
1997.000000 11.000000 -2.000122 4.000488 -22.001343 12.278182
1998.000000 13.000000 -1.000122 1.000244 -13.001587 13.194591
1999.000000 14.000000 -0.000122 0.000000 -0.001709 14.110999
2000.000000 17.000000 0.999878 0.999756 16.997925 15.027407
2001.000000 18.000000 1.999878 3.999512 35.997803 15.943815
2002.000000 15.000000 2.999878 8.999268 44.998169 16.860224
2003.000000 17.000000 3.999878 15.999023 67.997925 17.776632
-----------------------------------------------------------------

y = 127.000000 xy = 54.984497 x2 = 60.000000
a = 14.111111 b = 0.916408

Enter the Year for finding the treand value : 2004

The Trend Values for Year 2004.000000 is 18.693041 */
  
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Harry Evans
Harry Evans author of PROGRAM TO FIND THE POSSIBLE VALUE OF ? SIGN USING TIME SERIES is from London, United Kingdom.
 
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