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Program to find number of days b/w two given dates

Posted By: Easy Tutor     Category: C++ Programming     Views: 10892

A C++ program to find number of days b/w two given dates.

Code for Program to find number of days b/w two given dates in C++ Programming

 #include<iostream.h>
 #include<conio.h>


 /*************************************************************************///------------------------------  day  ----------------------------------///*************************************************************************/class day
    {
       private:
        int date;
        int month;
        int year;

       public:
        day()  {  date=0; month=0; year=0;  }
        void get_date();
        void show_days(day,day);
        void show_date();
        int next_month(int,int);
        int next_year(int);
        intoperator>(day);
    };

 /*************************************************************************///---------------------------  get_date( )  -----------------------------///*************************************************************************/void day::get_date()
    {
       cout<<"\tEnter the date = ";
       cin>>date;

       cout<<"\tEnter the month = ";
       cin>>month;

       cout<<"\tEnter the year = ";
       cin>>year;
    }

 /*************************************************************************///--------------------------  show_date( )  -----------------------------///*************************************************************************/void day::show_date()
    {
       cout<<"\n\t Date is     ";
       cout<<((date<10)?"0":"")<<this->date<<" : ";
       cout<<((month<10)?"0":"")<<this->month<<" : "<<this->year<<endl;
    }

 /*************************************************************************///---------------------------  show_days(day,day)  ----------------------///*************************************************************************/void day::show_days(day d1,day d2)
    {
    long d=0;

    if(d2.date<d1.date && d2.month!=d1.month && d2.year>=d1.year)
       {
          d2.date+=next_month(d2.month-1,d2.year);
          d2.month--;
       }

    for(int count_1=d1.date;count_1<d2.date;count_1++)
       d++;

    if(d2.month<d1.month && d2.year>d1.year)
       {
          d2.month+=12;
          d2.year--;
       }

    for(int count_2=d1.month;count_2<d2.month;count_2++)
       d+=next_month(count_2,d1.year);

    for(int count_3=d1.year;count_3<d2.year;count_3++)
       d+=365+next_year(count_3);

    cout<<"\t Number of days b/w date1 & date2 = "<<d<<" days"<<endl;
    }

 /*************************************************************************///---------------------------  operator>(day)  --------------------------///*************************************************************************/int day::operator>(day d)
    {
       long d1;
       long d2;

       d2=date+(month*30)+(year*360);
       d1=d.date+(d.month*30)+(d.year*360);
       return (d2>d1?1:0);
    }

 /*************************************************************************///-------------------------  next_month(int,int)  -----------------------///*************************************************************************/int day::next_month(int m,int y)
    {
       int d;

       if(m<1)
      m+=12;

       elseif(m>12)
      m-=12;

       switch(m)
      {
         case 1 : d=31;
              break;

         case 2 : d=28+next_year(y);
              break;

         case 3 : d=31;
              break;

         case 4 : d=30;
              break;

         case 5 : d=31;
              break;

         case 6 : d=30;
              break;

         case 7 : d=31;
              break;

         case 8 : d=31;
              break;

         case 9 : d=30;
              break;

         case 10 : d=31;
              break;

         case 11 : d=30;
              break;

         case 12 : d=31;
              break;
      }

       return d;
    }

 /*************************************************************************///---------------------------  next_year(int)  --------------------------///*************************************************************************/int day::next_year(int y)
    {
       if(y%4==0 || y%4==0 || y%100==0)
      return 1;

       elsereturn 0;
    }

 /*************************************************************************//*************************************************************************///-----------------------------  Main( )  -------------------------------///*************************************************************************//*************************************************************************/

 main()
    {
       clrscr();

       day date_1;
       day date_2;
       day date_3;

       cout<<"\n Enter the date in the pattern i.e  dd/mm/yy "<<endl;

       cout<<"\n  First Date :"<<endl;
       date_1.get_date();

       cout<<"\n  Second Date :"<<endl;
       date_2.get_date();

       cout<<"\n********** First Date **********"<<endl;
       date_1.show_date();

       cout<<"\n********** Second Date **********"<<endl;
       date_2.show_date();

       cout<<"\n********** Result **********\n"<<endl;
       if(date_1>date_2)
      date_3.show_days(date_2,date_1);

       else
      date_3.show_days(date_1,date_2);

       getch();
       return 0;
    }
  
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