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# Compute sum of those integers that are evenly divisible by 5. Use the conditional operator ( ? : ).

Posted By: Falaknaz Ahmed     Category: C Programming     Views: 9927

## Code for Compute sum of those integers that are evenly divisible by 5. Use the conditional operator ( ? : ). in C Programming

```#include<stdio.h>
#include<conio.h>
void main()
{
int i,sum=0,n=100,j=0;
clrscr();
printf("\n\n THE SERIES IS UNDER : \n\n\n");
i=2;
while(i<=n)
{
sum=sum+i;
i==2 ? printf("%d",i):printf(" + %d",i);
i=i+3;
}
printf("\n\n\n THE SUMMATION OF SERIES IS %d",sum);
printf("\n\n\n");
i=2;
while(i<=n)
{
sum=sum+i;
i%5==0 ? j=j+i:0;
i==5 ? printf("%d",i):0;
i%5==0 ? printf(" + %d",i):0;
i=i+3;
}
printf("\n\n\n THE SUMMATION OF DIVISIBLE 5 IS %d",j);
getch();
}

*************************** OUTPUT *******************************************

THE SERIES IS UNDER :

2 + 5 + 8 + 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 + 44 + 47 + 50 + 53 + 56 + 59 + 62 + 65 + 68 + 71 + 74 + 77 + 80 + 83 + 86 + 89 + 92 + 95 + 98

THE SUMMATION OF SERIES IS 1650

5 + 5 + 20 + 35 + 50 + 65 + 80 + 95

THE SUMMATION OF DIVISIBLE 5 IS 350

*******************************************************************************```
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 Falaknaz Ahmed author of Compute sum of those integers that are evenly divisible by 5. Use the conditional operator ( ? : ). is from Karachi, Pakistan. View All Articles

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