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# Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement

Posted By: Hedwig Miller     Category: C Programming     Views: 10396

## Code for Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement in C Programming

```#include<stdio.h>
#include<conio.h>
void main()
{
int i,sum=0,n=100,j=0;
clrscr();
printf("\n\n THE SERIES IS UNDER : \n\n\n");
i=2;
while(i<=n)
{
sum=sum+i;
if(i==2)
printf("%d",i);
else
printf(" + %d",i);
i=i+3;
}

printf("\n\n\n THE SUMMATION OF SERIES IS %d",sum);
printf("\n\n\n");
i=2;
while(i<=n)
{
sum=sum+i;
if(i%5==0)
{
if(i==5)
printf("%d",i);
else
printf(" + %d",i);
j=j+i;
}
i=i+3;
}
printf("\n\n\n THE SUMMATION OF DIVISIBLE 5 IS %d",j);
getch();
}

--------------------------------- OUTPUT ---------------------------------

THE SERIES IS UNDER :

2 + 5 + 8 + 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 + 44 + 47 + 50
+ 53 + 56 + 59 + 62 + 65 + 68 + 71 + 74 + 77 + 80 + 83 + 86 + 89 + 92 + 95 + 98

THE SUMMATION OF SERIES IS 1650

5 + 20 + 35 + 50 + 65 + 80 + 95

THE SUMMATION OF DIVISIBLE 5 IS 350

--------------------------------------------------------------------------```
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 Hedwig Miller author of Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement is from Frankfurt, Germany. View All Articles

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