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Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement

Posted By: Hedwig Miller     Category: C Programming     Views: 5603

Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement.

Code for Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement in C Programming

#include<stdio.h>
#include<conio.h>
void main()
{
    int i,sum=0,n=100,j=0;
    clrscr();
    printf("\n\n THE SERIES IS UNDER : \n\n\n");
    i=2;
    while(i<=n)
    {
        sum=sum+i;
        if(i==2)
            printf("%d",i);
        else
            printf(" + %d",i);
        i=i+3;
    }

    printf("\n\n\n THE SUMMATION OF SERIES IS %d",sum);
    printf("\n\n\n");
    i=2;
    while(i<=n)
    {
        sum=sum+i;
        if(i%5==0)
        {
            if(i==5)
                printf("%d",i);
            else
                printf(" + %d",i);
            j=j+i;
        }
        i=i+3;
    }
    printf("\n\n\n THE SUMMATION OF DIVISIBLE 5 IS %d",j);
getch();
}


--------------------------------- OUTPUT ---------------------------------




 THE SERIES IS UNDER :


2 + 5 + 8 + 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 + 44 + 47 + 50
+ 53 + 56 + 59 + 62 + 65 + 68 + 71 + 74 + 77 + 80 + 83 + 86 + 89 + 92 + 95 + 98


 THE SUMMATION OF SERIES IS 1650


5 + 20 + 35 + 50 + 65 + 80 + 95


 THE SUMMATION OF DIVISIBLE 5 IS 350

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Hedwig Miller
Hedwig Miller author of Program to compute sum of those integers that are evenly divisible by 5 Use if-else statement is from Frankfurt, Germany.
 
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