Logo 
Search:

C Programming Articles

Submit Article
Home » Articles » C Programming » Mathematics ProgramRSS Feeds

Program to transpose a sparse matrix

Posted By: Viveka Fischer     Category: C Programming     Views: 8823

Program to transpose a sparse matrix.

Code for Program to transpose a sparse matrix in C Programming

#include <stdio.h>
#include <conio.h>
#include <alloc.h>

#define MAX1 3
#define MAX2 3

struct sparse
{
    int *sp ;
    int row ;
} ;

void initsparse ( struct sparse * ) ;
void create_array ( struct sparse * ) ;
void display ( struct sparse ) ;
int count ( struct sparse ) ;
void create_tuple ( struct sparse *, struct sparse ) ;
void display_tuple ( struct sparse ) ;
void transpose ( struct sparse *, struct sparse ) ;
void display_transpose ( struct sparse ) ;
void delsparse ( struct sparse * ) ;

void main( )
{
    struct sparse s[3] ;
    int c, i ;

    for ( i = 0 ; i <= 2 ; i++ )
        initsparse ( &s[i] ) ;

    clrscr( ) ;

    create_array ( &s[0] ) ;

    printf ( "\nElements in Sparse Matrix: " ) ;
    display ( s[0] ) ;

    c = count ( s[0] ) ;
    printf ( "\n\nNumber of non-zero elements: %d", c ) ;

    create_tuple ( &s[1], s[0] ) ;
    printf ( "\n\nArray of non-zero elements: " ) ;
    display_tuple ( s[1] ) ;

    transpose ( &s[2], s[1] ) ;
    printf ( "\n\nTranspose of array: " ) ;
    display_transpose ( s[2] ) ;

    for ( i = 0 ; i <= 2 ; i++ )
        delsparse ( &s[i] ) ;

    getch( ) ;
}

/* initialises data members */
void initsparse ( struct sparse *p ) { p -> sp = NULL ; } /* dynamically creates the matrix of size MAX1 x MAX2 */
void create_array ( struct sparse *p ) { int n, i ; p -> sp = ( int * ) malloc ( MAX1 * MAX2 * sizeof ( int ) ) ; for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { printf ( "Enter element no. %d:", i ) ; scanf ( "%d", &n ) ; * ( p -> sp + i ) = n ; } } /* displays the contents of the matrix */
void display ( struct sparse s ) { int i ; /* traverses the entire matrix */
for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { /* positions the cursor to the new line for every new row */
if ( i % MAX2 == 0 ) printf ( "\n" ) ; printf ( "%d\t", * ( s.sp + i ) ) ; } } /* counts the number of non-zero elements */
int count ( struct sparse s ) { int cnt = 0, i ; for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { if ( * ( s.sp + i ) != 0 ) cnt++ ; } return cnt ; } /* creates an array that stores information about non-zero elements */
void create_tuple ( struct sparse *p, struct sparse s ) { int r = 0 , c = -1, l = -1, i ; p -> row = count ( s ) + 1 ; p -> sp = ( int * ) malloc ( p -> row * 3 * sizeof ( int ) ) ; * ( p -> sp + 0 ) = MAX1 ; * ( p -> sp + 1 ) = MAX2 ; * ( p -> sp + 2 ) = p -> row - 1 ; l = 2 ; for ( i = 0 ; i < MAX1 * MAX2 ; i++ ) { c++ ; /* sets the row and column values */
if ( ( ( i % MAX2 ) == 0 ) && ( i != 0 ) ) { r++ ; c = 0 ; } /* checks for non-zero element
row, column and non-zero element value
is assigned to the matrix */
if ( * ( s.sp + i ) != 0 ) { l++ ; * ( p -> sp + l ) = r ; l++ ; * ( p -> sp + l ) = c ; l++ ; * ( p -> sp + l ) = * ( s.sp + i ) ; } } } /* displays the contents of 3-tuple */
void display_tuple ( struct sparse p ) { int i ; for ( i = 0 ; i < p.row * 3 ; i++ ) { if ( i % 3 == 0 ) printf ( "\n" ) ; printf ( "%d\t", * ( p.sp + i ) ) ; } } /* obtains transpose of an array */
void transpose ( struct sparse *p, struct sparse s ) { int x, q, pos_1, pos_2, col, elem, c, y ; /* allocate memory */
p -> sp = ( int * ) malloc ( s.row * 3 * sizeof ( int ) ) ; p -> row = s.row ; /* store total number of rows, cols
and non-zero elements */
* ( p -> sp + 0 ) = * ( s.sp + 1 ) ; * ( p -> sp + 1 ) = * ( s.sp + 0 ) ; * ( p -> sp + 2 ) = * ( s.sp + 2 ) ; col = * ( p -> sp + 1 ) ; elem = * ( p -> sp + 2 ) ; if ( elem <= 0 ) return ; x = 1 ; for ( c = 0 ; c < col ; c++ ) { for ( y = 1 ; y <= elem ; y++ ) { q = y * 3 + 1 ; if ( * ( s.sp + q ) == c ) { pos_2 = x * 3 + 0 ; pos_1 = y * 3 + 1 ; * ( p -> sp + pos_2 ) = * ( s.sp + pos_1 ) ; pos_2 = x * 3 + 1 ; pos_1 = y * 3 + 0 ; * ( p -> sp + pos_2 ) = * ( s.sp + pos_1 ) ; pos_2 = x * 3 + 2 ; pos_1 = y * 3 + 2 ; * ( p -> sp + pos_2 ) = * ( s.sp + pos_1 ) ; x++ ; } } } } /* displays 3-tuple after transpose operation */
void display_transpose ( struct sparse p ) { int i ; for ( i = 0 ; i < p.row * 3 ; i++ ) { if ( i % 3 == 0 ) printf ( "\n" ) ; printf ( "%d\t", * ( p.sp + i ) ) ; } } /* deallocates memory */
void delsparse ( struct sparse *p ) { free ( p -> sp ) ; }
  
Share: 


Didn't find what you were looking for? Find more on Program to transpose a sparse matrix Or get search suggestion and latest updates.

Viveka Fischer
Viveka Fischer author of Program to transpose a sparse matrix is from Frankfurt, Germany.
 
View All Articles

 
Please enter your Comment

  • Comment should be atleast 30 Characters.
  • Please put code inside [Code] your code [/Code].

 
No Comment Found, Be the First to post comment!