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  Question Asked By: Karina K patni   on Aug 04 In Java Category.

  
Question Answered By: Frank Butler   on Aug 04

More a C++ person than a Java person, but ...

I don't think "a.super ()" is valid (or at least relevant). Parameter "a" is of
type "A" and class  "A" doesn't have a specified parent class.

I assume the parameter "a" will contain a reference to the associated "A" class
item. Why not then use "a.test()"?

> This also serves as proof to see if we have any advanced  Java people here!

This is very rude. I'm sure the capabilities of the people on this list range
between beginner and guru. Where do you sit on this range?

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