const int size = 5;
void print(int *ptr)
{
cout<<ptr[0];
}

void print(int ptr[size])
{
cout<<ptr[0];
}

void main()
{
int a[size] = {1,2,3,4,5};
int *b = new int(size);
print(a);
print(b);
}


Answer:
Compiler Error : function 'void print(int *)' already has a body


Explanation:
Arrays cannot be passed to functions, only pointers (for arrays, base addresses)
can be passed. So the arguments int *ptr and int prt[size] have no difference
as function arguments. In other words, both the functoins have the same signature and
so cannot be overloaded.