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Program to calculate anybody’s single digit lucky number

Posted By: Easy Tutor     Category: C++ Programming     Views: 10359

Write a program to calculate anybody’s single digit lucky number using the following scenario;

- Replace all alphabets of anybody’s name with number of that alphabet e.g. replace ‘a’ with 1, ‘b’ with 2 and ‘c’ with 3.
- Add all numbers until it becomes a single digit e.g.

For name Annu = 1+14+14+21
= 50
= 5+0
= 5
so, Annu’s lucky number is 5.

Note:
Print invalid if the name contains a character other than alphabets e.g. Space, Dot, Numbers, etc. The input will contain multiple test cases and will end on the line that contains 0.

Code for Program to calculate anybody’s single digit lucky number in C++ Programming

 # include <iostream.h>
 # include <fstream.h>
 # include <string.h>
 # include <stdlib.h>
 # include <conio.h>
 # include <ctype.h>

 int main( )
    {
       clrscr( );

       fstream File("CP-07.txt",ios::in|ios::nocreate);

       if(!File)
      {
         cout<<"Unable to open the input file."<<endl;
         cout<<"Press any key to exit."<<endl;

         getch( );
         exit(EXIT_FAILURE);
      }

       char Data[100]={NULL};

       do
      {
         strset(Data,NULL);

         File.getline(Data,80,'\n');

         if(strcmpi(Data,"0")==0)
        break;

         int flag=0;
         int name_length=strlen(Data);

         int code_array[100]={0};

         for(int count_1=0;count_1<name_length;count_1++)
        {
           if(!isalpha(Data[count_1]))
              {
             flag=1;

             break;
              }

           else
              {
             Data[count_1]=toupper(Data[count_1]);

             code_array[count_1]=(int(Data[count_1])-64);
              }
        }

         if(!flag)
        {
           int lucky_number=0;

           for(int count_2=0;count_2<name_length;count_2++)
              lucky_number+=code_array[count_2];

           char Lucky_number[100]={NULL};

           while(lucky_number>9)
              {
             strset(Lucky_number,NULL);
             itoa(lucky_number,Lucky_number,10);

             lucky_number=0;

             int number_length=strlen(Lucky_number);

             char Digit[5]={NULL};

             for(int count_3=0;count_3<number_length;count_3++)
                {
                   Digit[0]=Lucky_number[count_3];

                   lucky_number+=atoi(Digit);
                }
              }

           cout<<lucky_number<<endl;
        }

         else
        cout<<"invalid"<<endl;
      }
       while(1);

       File.close( );

       getch( );
       return 0;
    }
  
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Easy Tutor
Easy Tutor author of Program to calculate anybody’s single digit lucky number is from United States. Easy Tutor says

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