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  Question Asked By: Lucas Ward   on Sep 22 In MS Office Category.

  
Question Answered By: Aaliyah Khan   on Sep 22

I think that won't work -- Factorial would multiply, and for
a weighted average  divisor, it would have to add the weights.

Got this working for the divisor, though:

=COUNT(OFFSET($N10,0,0,-BK$2,1))*
(1+COUNT(OFFSET($N10,0,0,-BK$2,1)))/2

Now, just need to make the array {1;2;3;4;5;6;7;8;9;10;11;12}
part "flexible"...

Don't know if that can be done; have also tried writing in
VBA, and have posted as separate msg.

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