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simple array

  Asked By: Molly    Date: Nov 16    Category: Java    Views: 785

i have a class that takes a user input of how many integers and then
takes in the same number of intergers. What I need to do is create
some sort of array and run throgh the input to get the smallest and
the largest etc. Here's code:

import java.util.ArrayList;

public class SelectionSort
public static void main( String[] args )

Terminal terminal = new Terminal();
int sortTotal;

sortTotal = terminal.readInt("Integers to sort: ");

int number[] = new int[sortTotal];

for (int i = 0; i < number.length; i++) {

int n = terminal.readInt("> ");




The output is:

Integers to sort: 3
> 2
> 4
> 6

can anybody get me started with a sort method.



4 Answers Found

Answer #1    Answered By: Baylen Smith     Answered On: Nov 16

> can anybody get me started  with a sort  method.

That's an easy one.

import java.util.Arrays;

Answer #2    Answered By: Lughaidh Fischer     Answered On: Nov 16

there are several sorting methods, I suggest you to start with the
simplest, just named "Simple Sort".
You can find explanation, source and a nice demo here

Answer #3    Answered By: Aalia Arain     Answered On: Nov 16

Yes this confirms what I was looking for
which was a nested for loop. Here is my code:

int[] numbers = new int[sortTotal];

for ( index = 0; index < numbers.length; index++) {

numbers[index] = terminal.readInt(">");

for (index = 0; index < numbers.length; index++){

min = index;
for ( j = index+1; j < numbers.length; j++){
if ( numbers[j] < numbers[min] )
min = j;

temp = numbers[index];
numbers[index] = numbers[min];
numbers[min] = temp;


Answer #4    Answered By: Terence Mitchell     Answered On: Nov 16

Try to use java  Collections. They are all so usefull.

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