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  Asked By: Nisha    Date: Aug 01    Category: Java    Views: 571

please help me, how can i solve taht nullpointer exception problem?
or i can't do so :

import java.util.*;
import java.io.*;
public class push{
public static void main(String args[])throws IOException{
Stack ma[]=new Stack[5];
int anothe[]={1,22,3,16,1};
String sk[]={"hi","it's","me","not","you"};
int i;

for (i=0; i<6; i++) {
} catch(RuntimeException e) {
System.out.print(e+" "+i);
for (i=0; i<24; i++) System.out.println(ma[i].pop());



1 Answer Found

Answer #1    Answered By: Kay Rodriguez     Answered On: Aug 01

Your first for loop goes from 0 to 5 that is 6 different elements and I
don't think you want 6 elements (both ma[] and sk[] are 5 elements
long). The challenge for you in this question is that you have two
different arrays feeding information.

I would look at using Stack ma = new Stack(); Instead of Stack ma[] =
new Stack[5]; I think that what you are doing currently is creating a
array of Stack Objects.

Now looping though a length of a collection is realy easy, in fact you
have probably seen a example of this in one of your tutes. If you type
arrayName.length or collectionName.getSize() it reports the size of the

for (int i = 0; i <= arrayName.length ; i++) will loop though the exact
size of the array.

Your second for loop is probably going to be broken too.

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