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Quirksome Square

  Asked By: Tishad    Date: Dec 10    Category: C Programming    Views: 2741
  

The number 3025 has a remarkable quirk: if you split its decimal representation
in two strings of equal length (30 and 25) and square the sum of the numbers so obtained, you obtain the
original number:
(30 + 25)
2
=3025
The problem is to determine all numbers with this property having a given even number of digits.
For example, 4-digit numbers run from 0000 to 9999. Note that leading zeroes should be taken into
account. This means that 0001 which is equal to is a quirksome number of 4 digits. The number of digits
may be 2,4,6 or 8. Although maxint is only 32767 and numbers of eight digits are asked for, a well-versed
programmer can keep his numbers in the range of the integers. However efficiency should be given a
thought.
Input
The input of your program is a textflle containing numbers of digits (taken from 2,4,6,8), each number on
a line of its own.
Output
The output is a textfile consisting of lines containing the quirksome numbers (ordered according to the
input numbers and for each input number in increasing order).
Warning: Please note that the number of digits in the output is equal to the number in the corresponding
input line : leading zeroes may not be suppressed.
Sample Input 2
2
Sample Output
00
01
81
00
01
81

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