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# NEWTON'S FORWARD DIFFERENCE METHOD

Posted By: Adelfried Fischer     Category: C Programming     Views: 39875

## Code for NEWTON'S FORWARD DIFFERENCE METHOD in C Programming

```#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float x[10],y[10][10],sum,p,u,temp;
int i,n,j,k=0,f,m;
float fact(int);
clrscr();
printf("\nhow many record you will be enter: ");
scanf("%d",&n);
for(i=0; i<n; i++)
{
printf("\n\nenter the value of x%d: ",i);
scanf("%f",&x[i]);
printf("\n\nenter the value of f(x%d): ",i);
scanf("%f",&y[k][i]);
}

printf("\n\nEnter X for finding f(x): ");
scanf("%f",&p);

for(i=1;i<n;i++)
{
for(j=0;j<n-i;j++)
{
y[i][j]=y[i-1][j+1]-y[i-1][j];
}
}
printf("\n_____________________________________________________\n");
printf("\n  x(i)\t   y(i)\t    y1(i)    y2(i)    y3(i)    y4(i)");
printf("\n_____________________________________________________\n");
for(i=0;i<n;i++)
{
printf("\n %.3f",x[i]);
for(j=0;j<n-i;j++)
{
printf("   ");
printf(" %.3f",y[j][i]);
}
printf("\n");
}

i=0;
do
{
if(x[i]<p && p<x[i+1])
k=1;
else
i++;
}while(k != 1);
f=i;
u=(p-x[f])/(x[f+1]-x[f]);
printf("\n\n u = %.3f ",u);

n=n-i+1;
sum=0;
for(i=0;i<n-1;i++)
{
temp=1;
for(j=0;j<i;j++)
{
temp = temp * (u - j);
}
m=fact(i);
sum = sum + temp*(y[i][f]/m);
}
printf("\n\n f(%.2f) = %f ",p,sum);
getch();
}

float fact(int a)
{
float fac = 1;

if (a == 0)
return (1);
else
fac = a * fact(a-1);

return(fac);
}

/*______________________________________         OUT PUT______________________________________how many record you will be enter: 5enter the value of x0: 2enter the value of f(x0): 9enter the value of x1: 2.25enter the value of f(x1): 10.06enter the value of x2: 2.5enter the value of f(x2): 11.25enter the value of x3: 2.75enter the value of f(x3): 12.56enter the value of x4: 3enter the value of f(x4): 14Enter X for finding f(x): 2.35_____________________________________________________  x(i)     y(i)     y1(i)    y2(i)    y3(i)    y4(i)_____________________________________________________ 2.000    9.000     1.060    0.130   -0.010    0.020 2.250    10.060    1.190    0.120    0.010 2.500    11.250    1.310    0.130 2.750    12.560    1.440 3.000    14.000 u = 0.400 f(2.35) = 10.522240*/```
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 Adelfried Fischer author of NEWTON'S FORWARD DIFFERENCE METHOD is from Frankfurt, Germany. View All Articles