Logo 
Search:

C++ Programming Articles

Submit Article
Home » Articles » C++ Programming » Numerical AnalysisRSS Feeds

Linear Interpolation

Posted By: Maaz Ahmed     Category: C++ Programming     Views: 9361

this program is used to calculate linear interpolation

#include<conio.h>
#include<stdio.h>
#include<stdlib.h>
#include<math.h>

int i=0,cnt=0,flag=0;
float x1,x2,x3=0;
float fx1=0,fx2=0,fx3=0,t=0;



float func(float f)
{
return(f*f-4*f+3);
}

int check()
{
printf("\n\tINTIAL X1---->");
scanf("%f",&x1);

printf("\n\tINTIAL X2---->");
scanf("%f",&x2);

fx1=fx2=fx3=0.0;


if( (func(x1)*func(x2))>0)
{
printf("\n\t INTIAL VALUES ARE NOT PERFECT.");
return(1);
}
return(0);
}
void main()
{
clrscr();


printf("\n\n\t\t\t PROGRAM FOR PARICULAR BISECTION GENERAL");
printf("\n\n\t EQUATION ::::");

while(1)
{
if(check()==0)
{
flag=1;
break;
}
check();
}
printf("\n ******************************************************");
printf("\n ITERATION X1 FX1 X2 FX2 X3 FX3 ");
printf("\n **********************************************************");

if(flag==1)
{
while((fabs(x2 - x1))>=0.0001)
{
cnt++;
fx1=fx2=fx3=0;

fx1=func(x1);
fx2=func(x2);

x3=((x1*fx2)-(x2*fx1))/(fx2-fx1);
fx3=func(x3);

printf("\n %d %.3f %.3f %.3f %.3f %.3f %.3f",cnt,x1,fx1,x2,fx2,x3,fx3);
t=fx1*fx3;
if(t>0)
{
x1=x3;
}
if(t<0)
{
x2=x3;
}
}
printf("\n\t ROOT OF EQUATION IS %f:::",x3);
}
getch();
}

  
Share: 


Didn't find what you were looking for? Find more on Linear Interpolation Or get search suggestion and latest updates.

Maaz  Ahmed
Maaz Ahmed author of Linear Interpolation is from Pakistan.
 
View All Articles

 
Please enter your Comment

  • Comment should be atleast 30 Characters.
  • Please put code inside [Code] your code [/Code].

 
No Comment Found, Be the First to post comment!